#11
STORM
Exercise
and
Assignment #5, PART 1
The problem:
Zmax = 5X1 + 3X2 + 4X3
subject to:
b1: X1 + 3X3 <= 30
b2: 2X2 + X3 >= 15
b3: 3X1 + 2X2 <= 10
Choose:
1) Linear & Integer Programming
Choose:
2) Create a new data set
Type in:
Title: STORM Exercise 1 your name
Number of variables: 3
Number of constraints: 3
Starting solution given: no
Objective type (MAX/MIN): MA
Ready to go on to detailed data?
Enter:
y
Change:
Three column labels: VAR 1, 2, 3 to X1, X2, X3
Change:
Three row labels: CONSTR 1, 2, 3 to b1, b2, b3
Enter:
the following in the OBJ COEFF row:
X1: 5
X2: 3
X3: 4
(See the objective function above in order to understand these values.)
Enter:
the values in the b1 row:
b1: X1: 1 X2: 0 X3: 3 RHS: 30
(See the constraints above in order to understand these values.)
Enter the values in the other two rows:
b2:
b3:
VARBL TYPE
This is nonnegativity. Keep as POS (the default value).
Hit:
<F7> Done
Choose:
4) Execute the module
Choose:
1) Go to the optimal solution
Choose:
2) Detailed report
Questions:
a) What are the BASIC variables in the optimal solution?
b) What are the values of each of these variables?
c) What is the profit?
d) So what is the optimal solution … in plain English?
Hit:
<Print Screen>
Hit:
<Enter> to get to next screen
Hit:
<Print Screen>
Another question:
e) What does "shadow price" mean?
Hint: Go back to the data entry screen and change the value of b1 from 30 to 31. Execute the model.
Go to the optimal solution.
Detailed report.
What has changed? Why? This should help explain what a "shadow price" is.
Save the file:
Get to the original screen and Choose:
2) Save the current data set on your disk.
Type in a filename
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Assignment #5, Part 1
BRING to class on Monday, March 20th
A) Enter the problem from Assignment #4 (handout #10) into STORM. Print (2 pages) and save the file. (Check values are: 30 tables, 40 chairs, profit $410.)
B) Enter the problem from the exercise for Junk Jewelry Inc. (handout #9) into STORM. Print (2 pages) and save the file. (Check values are: X1=4, X2=3, S3=1, profit=$2400.)
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