1. Using dots to represent rectangles (don’t worry about the color), draw the shape that the following segment of code displays.

#include "rect.h"SimpleWindow MyWin("My shape", 17.0, 9.0);
int ApiMain() {
     MyWin.Open() ;
     // Draw a rectangle made up of red and blue squares
     for (int i=1; i<=5; i++) {
        for (int j=1; j<=5; j++) {
           if ( j >= i) {
             RectangleShape R1(MyWin,  i, j, Blue, 0.75, 0.75) ;
             R1.Draw();
           }
        }
     }  
    return 0 ;
}

 

  .
  . .
  . . .
  . . . .
  . . . . .

 

2. What will the following segment of code print?

#include <iostream>
using namespace std;
int main(){   
   for (int count = 1; count < 10; count++) { 
     cout << "counting backwards to 1 starting with " << count << ": ";
     switch (count) {       
         case 10:
            cout << "ten ";
         case 9:
            cout << "nine ";
        case 8:
            cout << "eight ";
         case 7:
           cout << "seven ";
         case 6:
            cout << "six ";
         case 5:
            cout << "five ";
         case 4:
            cout << "four ";
         case 3:
            cout << "three ";
         case 2:
            cout << "two ";
         case 1:
            cout << "one" << endl;
      }
   }
   return 0;
}

 

 
When the missing bracket is added as shown above the output is:

counting backwards to 1 starting with 1: one
counting backwards to 1 starting with 2: two one
counting backwards to 1 starting with 3: three two one
counting backwards to 1 starting with 4: four three two one
counting backwards to 1 starting with 5: five four three two one
counting backwards to 1 starting with 6: six five four three two one
counting backwards to 1 starting with 7: seven six five four three two one
counting backwards to 1 starting with 8: eight seven six five four three two one
counting backwards to 1 starting with 9: nine eight seven six five four three two one

 

3. Write a for loop that calculates the sum of the numbers 1 through 10.

 

  for(int i = 1, int sum = 0; i < 11; i++) 
     sum += i;

 

4. Write a function that takes two integer numbers as input and returns their sum.

 

  int sum (int a, int b)
  {
     return a+b;
  }

 

5. Write a program that prompts the user to enter a positive integer number, computes the square root of that number, and then prints the square root of that number to the monitor.

 

#include <fstream.h>
#include <math.h>
int main() {
   cout << "Enter a positive integer" << endl;
   int Value = 0;
   cin >> Value;
   cout << "The square root of that integer is: " << sqrt(Value) << endl;
   return 0;
}

 

6. Write a while loop that prompts the user to enter an integer number that is greater than 0 and less than 10 until the user does actually enter a number that matches those requirements.

 

  int value = 0;
  while(value < 1 || value > 9) {
        cout << "Enter a integer between 1 and 9" << endl;
        cin >> value;
  }

 

7. Explain what the line of code pointed to by 1 in the program below is doing.

<#include <fstream.h>
int main() {
   ifstream fin("mydata.txt");   ç== 1
   int ValuesProcessed = 0;
   float ValueSum = 0;
   float Value;
   while (fin >> Value) {
      ValueSum += Value;
      ++ValuesProcessed;
   }
   if (ValuesProcessed > 0) {
      ofstream fout("average.txt");
      float Average = ValueSum / ValuesProcessed;
      fout << "Average: " << Average << endl;
   }
   else
      cerr << "No list to average" << endl;
   return 0;
}

 

An object of type ifstream is declared.  The identifier for that object is fin 
and it opens the file mydata.txt for reading.

 

8. What will the program below print?

#include <iostream.h>
void Swap(int Value1, int Value2) {
   int Temp = Value1;
   Value1 = Value2;
   Value2 = Temp;
   return;
}

int main() {
   int Number1 = 4;
   int Number2 = 3;
   if (Number1 > Number2) {
      Swap(Number1, Number2);
   }
   cout << "The numbers in sorted order:"
        << Number1 << ", " << Number2 << endl;
   return 0;
}

 

  The numbers in sorted order: 4, 3

 

9. What is the data type of the value that will be returned by the function whose prototype is given below? What does this mean?

   void fun(int a, int b);

 

The return type void means that the function does not return anything.

 

10. What will be printed by the following code segment:

   #include <iostream.h>
   int i = 10;

   void fun() {
       {       
          int i = 1;
          cout << i << endl; 
          {
              float i = 3.2;
              cout << i << endl;    
              char i = 'a';
              cout << i << endl;    
           }
           cout << i << endl;       
       }
       cout << i << endl;       
   }

There is a compilation error in the above code because the identifier i is declared
twice in the same block.  This question was thrown out.