Assume x is a C integer variable. Show how you would set bits 5, 7, and 9 of x to 1 and clear bits 11 and 13 to 0 in one C-statment.
"x
= (x
| 0x280) & ~0x2800 ;".
Take the R-S latch in Figure 3.17 (p. 61) and replace the two NAND gates with two NOR gates. Show that the modified latch is stable if S, R, and a are all 0 while b is 1.
In this situation a, being 0, is connected to the output of NOR(S, b) or NOR(0, 1); and b, being 1, is connected to NOR(R, a) or NOR(0, 0). Because the present values a and b are consistent with the NOR gate outputs, the circuit is stable.
Now raise R to 1. What happens to your modified latch?
The bottom NOR is now computing NOR(1, 0). This makes its output, b, change to 0. This zero propagates to the top NOR which is now computing NOR(0, 0). So its output, a now changes to 1. The one propagates down to the bottom NOR, which is now computing NOR(1, 1). However, its output, b remains 0. So we enter a new stable state where a is 1 and b is 0.
Finally lower R back to 0. Again, what happens to your modified latch?
Though the bottom NOR is now computing NOR(0, 1), its output remains at 0. Consequently, a and b do not change values.
Decode the following LC/2 binary instructions, specified as hexadecimal numbers. That is, determine the type (opcode) of each instruction and specify its fields:
0000 | BR x0 |
0246 | BRp x046 |
1545 | ADD R2 R5 R5 |
1FFF | ADD R7 R7 -1 |
4444 | JSR R0 x144 |
6666 | LDR R3 R1 38 |
8000 | RTI |
99BF | NOT R4 R6 |
BBBB | STI R5 x1BB |
F035 | TRAP x35 |