# Quiz 2 2nd chance -- 9 April, 1997

This is a 2nd chance at Quiz 2. Your recorded grade for quiz two
will be calculated according to the following formula

`recorded-grade` = max(`grade-try1`, .9*`grade-try2`)

This is an open book, open notes exam; however, the use of
calculators is forbidden. The exam is to be turned in by 5:30 PM.

## Problem 1. (20 points)

How many address lines and data lines are needed for a
32M×8 memory?

## Problem 2. (20 points)

Convert the binary number 11001100 into a decimal number.

## Problem 3. (20 points)

Convert -100 into a ten-bit two's complement binary number.

## Problem 4. (20 points)

Convert the decimal number 15.15 into a floating point number
with one sign bit, an eight-bit exponent expressed using excess-127
notation, and a 23-bit mantissa.

## Problem 5. (20 points)

Describe how to construct an 8-to-1 multiplexer from three
4-to-1 multiplexers. *Do not* draw any gate level pictures
of the 4-to-1 multiplexer. Instead use a block diagram similar to
that seen below.

to represent the 4-to-1 multiplexer. The specification of this
multiplexer is found in Table 2-3 on page 49 of the textbook.

Write your answer on the back of this sheet.