Vending machine example -- Part II
The state table
x y A B z A B JA KA JB KB
0 0 0 0 0 0 0 0 x 0 x
0 0 0 1 0 0 1 0 x x 0
0 0 1 0 0 1 0 x 0 0 x
0 0 1 1 0 1 1 x 0 x 0
0 1 0 0 0 0 1 0 x 1 x
0 1 0 1 0 1 0 1 x x 1
0 1 1 0 0 1 1 x 0 1 x
0 1 1 1 0 1 1 x 0 x 0
1 0 0 0 0 1 0 1 x 0 x
1 0 0 1 0 1 1 1 x x 0
1 0 1 0 0 1 1 x 0 1 x
1 0 1 1 0 1 1 x 0 x 0
1 1 0 0 0 0 0 0 x 0 x
1 1 0 1 0 0 1 0 x x 0
1 1 1 0 0 1 0 x 0 0 x
1 1 1 1 1 0 0 x 1 x 1
The Equations
- z = Sigma(15)
- z = x y A B
- DA = Sigma(2, 3, 5, 6, 7, 8, 9, 10, 11, 14)
- DA = x' A + x' y B + x y' + A B'
- DB = Sigma(1, 3, 4, 6, 7, 9, 10, 11,13)
- DB = x' y B' + x' A B + x y' A + x A' B + y' B
- JA = Sigma(5, 8, 9)
- JA = d(2, 3, 6, 7, 10, 11, 14, 15)
- JA = x y' + x' y B
- KA = Sigma(15)
- KA = d(0, 1, 4, 5, 8, 9, 12, 13)
- KA = x y B
- JB = Sigma(4, 6, 10)
- JB = d(1, 3, 5, 7, 9, 11, 13, 15)
- JB = x' y + x y' A
- KB = Sigma(5, 15)
- KB = d(0, 2, 4, 6, 8, 10, 12, 14)
- KB = x' y A' + x y A
Implementation with D flip-flops
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Implementation with JK flip-flops
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